A) \[\frac{18}{3}\]m behind the mirror
B) \[\frac{18}{3}\] m infront of the mirror
C) \[\frac{4}{9}\]m behind the mirror
D) \[\frac{4}{9}\]m infront of the mirror
Correct Answer: C
Solution :
Given, \[f=\frac{1.6}{2}=0.8\,m\] and \[u=-1\,m\] \[\frac{1}{f}=\frac{1}{v}-\frac{1}{u}\] \[\frac{1}{v}=\frac{1}{0.8}-\frac{1}{-1}=\frac{10}{8}+1=\frac{9}{4}\] \[\Rightarrow \] \[v=\frac{4}{9}m\]
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