A) pyrosulphurous acid
B) hyposulphurous acid
C) pyrosulphuric acid
D) persulphuric acid
Correct Answer: A
Solution :
The structure of the given oxoacids of sulphur are as \[\underset{pyrosulphurous\text{ }acid}{\mathop{HO-\overset{\begin{smallmatrix} O \\ |{{|}_{+3}} \end{smallmatrix}}{\mathop{S}}\,-\overset{\begin{smallmatrix} O \\ |{{|}_{+5}} \end{smallmatrix}}{\mathop{\underset{\underset{O}{\mathop{||}}\,}{\mathop{S}}\,}}\,-OH}}\,\,\,\,\underset{hyposulphurous\text{ }acid}{\mathop{HO-\overset{\begin{smallmatrix} O \\ _{+3}|| \end{smallmatrix}}{\mathop{S}}\,-\overset{\begin{smallmatrix} O \\ |{{|}_{+3}} \end{smallmatrix}}{\mathop{S}}\,-OH}}\,\] \[\underset{pyrosulphuric\text{ }acid}{\mathop{HO-\overset{\begin{smallmatrix} O \\ {{ & }_{+6}}|| \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{S}}\,}}\,-O-\overset{\begin{smallmatrix} O \\ _{+6}|| \end{smallmatrix}}{\mathop{\underset{\underset{O}{\mathop{||}}\,}{\mathop{S}}\,}}\,-OH}}\,\] \[\underset{peroxodisulphuric\text{ }acid}{\mathop{HO-\overset{\begin{smallmatrix} O \\ {{ & }_{+6}}|| \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} || \\ O \end{smallmatrix}}{\mathop{S}}\,}}\,-O-O-\overset{\begin{smallmatrix} O \\ _{+6}|| \end{smallmatrix}}{\mathop{\underset{\underset{O}{\mathop{||}}\,}{\mathop{S}}\,}}\,-OH}}\,\] Thus, the oxidation states of two S atoms in pyrosulphurous acid are different.
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