A) +1,-1. 0
B) -1,+1, 0
C) +1,+1.0
D) -1.-1,0 .
Correct Answer: B
Solution :
Formal charge \[=\left[ \begin{align} & Total\text{ }number\text{ }of\text{ }valence \\ & electrons\text{ }in\text{ }the\text{ }free\text{ }atom \\ \end{align} \right]\] \[-\left[ \begin{align} & Total\text{ }number\text{ }of \\ & non-bonding\text{ }(lone \\ & pair)\text{ }electrons \\ \end{align} \right]-\frac{1}{2}\left[ \begin{align} & Total\text{ }number\text{ }of \\ & bonding\text{ (}shared) \\ & electrons \\ \end{align} \right]\]In \[_{\bullet }^{\bullet }\overset{\bullet \bullet }{\mathop{\underset{(1)}{\mathop{N}}\,}}\,=\underset{(2)}{\mathop{N}}\,=\overset{\bullet \bullet }{\mathop{O}}\,_{\bullet }^{\bullet }\] structure the formal charge on... the end N atom marked 1, \[=5-4-\frac{1}{2}\,(4)=5-4-2=-1\] the central N atom marked 2, \[=5-0-\frac{1}{2}\,(8)=5-4=+1\] the end O atom, \[=6-4-\frac{1}{2}\,(4)=6-6=0\]
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