A) 3 : 2; 5
B) 5 : 2 : 3
C) 5 : 3 : 2
D) 2 : 3 : 5
Correct Answer: A
Solution :
Lowering of vapour pressure is a colligative property. It depends on the number of particles of the solute. \[BaC{{l}_{2}}B{{a}^{2+}}+2C{{l}^{-}};\,3\,\,ions\] \[NaClN{{a}^{+}}+C{{l}^{-}};\,\,2\,ions\] \[A{{l}_{2}}{{(S{{O}_{4}})}_{3}}2A{{l}^{3+}}+3SO_{4}^{3-};\,\,5\,ions\] Hence, the ratio of lowering of vapour pressure is 3 : 2 : 5
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