A) 300
B) 500
C) 200
D) 100
Correct Answer: B
Solution :
The power gain is defined as the ratio of change in output to the change in input power. Since, P = VI Therefore, Power gain = Current gain \[\times \] Voltage gain \[=\beta \times \beta \left( \frac{{{R}_{out}}}{{{R}_{in}}} \right)={{\beta }^{2}}\left( \frac{{{R}_{out}}}{{{R}_{in}}} \right)\] Given, \[\beta =10,\,\,{{R}_{in}}=20\,k\Omega \] and \[{{R}_{out}}=100\,\,k\Omega \] Power gain \[={{(10)}^{2}}\left( \frac{100}{20} \right)=100\times 5=500\]
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