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BCECE Medical BCECE Medical Solved Papers-2015

  • question_answer
    The energy required to excite the electron in the atom from \[n=1\] to \[n=2\], when the ionization enthalpy of hydrogen atom is \[1.312\times {{10}^{6}}J/mol\] will be (in the unit of \[{{10}^{5}}\]).

    A)  8.53               

    B)  7.51

    C)  8.92               

    D)  9.86

    Correct Answer: D

    Solution :

     \[{{E}_{2}}=\frac{-1.312\times {{10}^{6}}\times {{(1)}^{2}}}{{{(2)}^{2}}}\]                 \[=-3.28\times {{10}^{-5}}J/mol\]                 \[{{E}_{1}}=-1.312\times {{10}^{6}}J/mol\] \[\therefore \] \[\Delta E={{E}_{2}}-{{E}_{1}}\]                 \[=-3.28\times {{10}^{5}}-(-1.312\times {{10}^{6}})\] \[=9.84\times {{10}^{5}}J/mol\]


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