A) zero
B) \[-\frac{1}{2}\,pV\]
C) \[-pV\]
D) \[-2\,\,pV\]
Correct Answer: C
Solution :
Net work done during the complete cycle is equal to area under the cycle and if the cycle is clockwise then negative, i.e. work done by the gas and when cycle is anti-clockwise then positive, i.e. work done on the gas \[W=-p\times V=-(2p-p)\times (2V-V)=-pV\]
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