A) 16.23%
B) 13.21%
C) 11.50%
D) 15.81%
Correct Answer: C
Solution :
Theoretical value of dipole moment of a 100% ionic character \[=e\times d\] \[=(1.60\times {{10}^{-19}}C)\,(1.41\times {{10}^{-10}}m)\] \[=2.26\times {{10}^{-29}}Cm\] Observed value of dipole moment \[=2.60\times {{10}^{-30}}Cm\] \[\therefore \] Per cent ionic character \[=\frac{Observed\text{ }value}{Theoretical\text{ }value}\times 100\] \[=\frac{2.60\times {{10}^{-30}}}{2.26\times {{10}^{-29}}}\times 100=11.5%\]
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