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BCECE Medical BCECE Medical Solved Papers-2015

  • question_answer
    Beryllium gives a compound X with the following percentage composition: Be-6.1%, N-37.8%, Cl-48%, H-8.1%. Molecular weight of X is \[148\,\,g\,mo{{l}^{-1}}\] and that of Be is \[9\,\,g\,mo{{l}^{-1}}\]. The molecular formula of the compound is

    A)  \[Be{{N}_{4}}C{{l}_{2}}{{H}_{12}}\]

    B)  \[Be{{N}_{2}}Cl{{H}_{6}}\]

    C)  \[Be{{N}_{4}}C{{l}_{2}}{{H}_{6}}\]

    D)  \[Be{{N}_{4}}Cl{{H}_{8}}\]

    Correct Answer: A

    Solution :

    Atom Atomic Weighty [a] % % Simplest ratio
    Be 9 6.1 0.68 1
    N 14 37.8 2.70 4
    Cl 35.5 48.0 1.35 2
    H 1 8.1 8.10 12
    \[\therefore \] The molecular formula is \[Be{{N}_{4}}C{{l}_{2}}{{H}_{12}}\].


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