A) \[F{{e}^{3+}}\] decreases
B) \[F{{e}^{3+}}\] increases
C) \[F{{e}^{2+}}\] decreases
D) \[F{{e}^{2+}},F{{e}^{3+}}\] remain unchanged
Correct Answer: A
Solution :
Cell reaction, \[2\,F{{e}^{3+}}+Fe\xrightarrow{{}}3F{{e}^{2+}}\] \[E_{cell}^{o}=0.77-(-0.44)=1.21\,V\] \[\Rightarrow \] \[F{{e}^{3+}}\] and Fe will reduce.
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