| I. \[CH=CH\] |
| II. \[C{{H}_{2}}=C{{H}_{2}}\] |
| III. \[{{H}_{2}}C=CH=Cl\] |
| IV. \[H\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,=\underset{\begin{smallmatrix} | \\ Cl \end{smallmatrix}}{\mathop{C}}\,H\] |
A) I > II > 111 > IV
B) ll > 1 > 111 > IV
C) IV > III > I > II
D) IV > III > I! > I
Correct Answer: B
Solution :
The order of electrophilic addition (EA) is alkene > alkyne. But, if alkene has EWG (electron withdrawing group) reactivity of alkene is less than that of alkyne. Due to EWG electron density at (C=C) or nucleophilicity decreases, so addition of electrophile to (C= C) is slow. So, the decreasing order of EA is (II)-(alkene) > (I)-(alkyne) > (III)-(alkene with one EWG) > (IV)-(alkene with two EWGs).
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