2. Solved Papers
  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    The equation of progressive wave is: \[y=0.2\sin 2\pi \left[ \frac{t}{0.01}-\frac{x}{0.3} \right]\]where\[x\]and\[y\]are in metre and t is in second.  The velocity of propagation of the wave is:

    A)  30 m/s                                

    B)  40 m/s

    C)  300 m/s                              

    D)  400 m/s

    Correct Answer: A

    Solution :

    Equation of the wave given \[y=0.02\sin 2\pi \left[ \frac{t}{0.01}-\frac{x}{0.3} \right]\]                                                   ?(1) The   standard   equation   of the progressive wave is \[y=0.02\sin 2\pi \left[ \frac{t}{T}-\frac{x}{\lambda } \right]\]                                ?(2) Comparing the given equation with the   standard   equation   of   the progressive wave, we get time period, \[T=0.01\,\sec .\] wavelength, \[\lambda =0.3\,m\] The frequency of the wave is given by \[v=\frac{1}{T}=\frac{1}{0.01}=100\,Hz\] Hence, the velocity of propagation of the wav \[\,\upsilon =v\lambda =100\times 0.3=30\,m/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner