A) \[\frac{{{C}_{1}}}{{{C}_{2}}}\]
B) \[\frac{C_{1}^{2}}{C_{2}^{2}}\]
C) \[\frac{{{V}_{1}}}{{{V}_{2}}}\]
D) \[\frac{V_{1}^{2}}{V_{2}^{2}}\]
Correct Answer: A
Solution :
Given: Capacitances of capacitors are\[{{C}_{1}}\]and \[{{C}_{2}}\]and potentials of the capacitors are\[{{V}_{1}}\]and \[{{V}_{2}}\] When the capacitors are connected in parallel then potential is same across each capacitors, but the charges are different. As it is from the formula for the charge on a capacitor is given by \[Q=CV\propto C\] Hence, \[\frac{{{Q}_{1}}}{{{Q}_{2}}}=\frac{{{C}_{1}}}{{{C}_{2}}}\]
You need to login to perform this action.
You will be redirected in
3 sec
