CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    Relative permeability of iron is 5500, then its magnetic susceptibility will be:

    A)  \[5500\times {{10}^{7}}\]                           

    B)  \[5500\times {{10}^{-7}}\]

    C)  \[5501\]                             

    D)  \[5499\]

    Correct Answer: D

    Solution :

    Relative    permeability    of    iron\[{{\mu }_{r}}=5500\] The    relation   between   relative permeability      and      magnetic susceptibility is given by                                 \[{{\mu }_{r}}=1+{{\chi }_{m}}\] (where\[{{\chi }_{m}}\] is  the   magnetic susceptibility)                                 \[5500=1+{{\chi }_{m}}\]                                 \[{{\chi }_{m}}=5500-1\]                                 \[=5499\]


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