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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    The force required to separate two glass plates of area \[{{10}^{-2}}{{\text{m}}^{\text{2}}}\]with a film of water 0.05 mm thick between them, is (Surface  tension   of   water   is \[70\times {{10}^{-3}}N/m\])

    A)  28 N                                     

    B)  14 N

    C)  50 N                                     

    D)  38 N

    Correct Answer: A

    Solution :

    Force required to separate the plates    \[F=\frac{2TA}{d}\] Given: area, \[A={{10}^{-2}}{{m}^{2}}\] thickness \[d=0.05\,mm=0.05\times {{10}^{-3}}\,m\] So,          \[F=\frac{2\times 10\times {{10}^{-3}}\times {{10}^{-2}}}{0.05\times {{10}^{-3}}}\]                 \[=28\,N\]


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