A) \[[M{{L}^{2}}{{T}^{-1}}]\]
B) \[[M{{L}^{-1}}{{T}^{-2}}]\]
C) \[[M{{L}^{2}}{{T}^{-2}}]\]
D) \[[ML{{T}^{-1}}]\]
Correct Answer: B
Solution :
The quantity \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}\]represents energy per unit volume. Thus, it has dimensions of \[\frac{\text{energy}}{\text{volume}}=\frac{[M{{L}^{2}}{{T}^{-2}}]}{[{{L}^{3}}]}=[M{{L}^{-1}}{{T}^{-2}}]\]
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