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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    When 9-65 coulombs of electricity is passed through a solution of silver nitrate     (atomic     mass     of\[Ag=108\,g\,mo{{l}^{-1}}\]), the amount of silver deposited is:

    A) 16 - 2 mg                               

    B) 21 - 2 mg

    C) 10 - 8 mg                              

    D) 6 - 4 mg

    Correct Answer: C

    Solution :

    Electricity passed \[=9.65\]coulombs The amount of silver deposited\[~=?\] We know that 96,500 coulombs \[=108\,mo{{l}^{-1}}\] \[\therefore \]\[9.65\]coulombs \[=\frac{9.65}{96500}\times 108=108\times {{10}^{-4}}gm=10.8\,mg\]


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