A) \[+914\,kJ\]
B) \[+\,97\,kJ\]
C) \[-\,97\,kJ\]
D) \[-194\,kJ\]
Correct Answer: B
Solution :
\[{{H}_{2}}+C{{l}_{2}}\xrightarrow{{}}2HCl,\Delta H=194\,kJ\] \[\therefore \] Heat of formation of \[\text{HCl}\] \[=\frac{194}{2}=97\,kJ\]You need to login to perform this action.
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