A) 5
B) 6
C) 3
D) 4
Correct Answer: A
Solution :
The electronic configuration of \[26\,Fe=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{6}}4{{s}^{2}}\] \[F{{e}^{+3}}=1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{5}}\] Therefore, the number of unpaired electrons \[=5\]
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