A) isopropyl iodide
B) 2-iodo propene
C) 2-iodopropane
D) 1-iodopropane
Correct Answer: C
Solution :
\[C{{H}_{3}}-\underset{\text{Propene}}{\mathop{\underset{C{{H}_{2}}}{\mathop{\underset{||}{\mathop{C}}\,}}\,}}\,H+\underset{I}{\overset{H}{\mathop{H}}}\,\xrightarrow{{}}\underset{\text{Isopropyl}\,\text{iodide}}{\mathop{\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}-CHI}{\mathop{|}}}\,}}\,\] This addition is due to Markownikoff rule. The negative part of addendum adds on to the less hydrogenated carbon atom.
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