A) \[\frac{\sin \sqrt{a}}{\sin (a+y)}\]
B) \[\frac{{{\sin }^{2}}(a+y)}{\sin a}\]
C) \[\frac{\sin (a+y)}{\sin a}\]
D) \[\frac{\cos (a+y)}{\cos a}\]
Correct Answer: B
Solution :
\[\sin y=x\sin (a+y)\Rightarrow x=\frac{\sin y}{\sin (a+y)}\] \[\Rightarrow \] \[\frac{dx}{dy}=\frac{\sin (a+y)\cos y-\sin y\cos (a+y)}{{{\sin }^{2}}(a+y)}\] \[\Rightarrow \]\[\frac{dx}{dy}=\frac{\sin (a+y-y)}{{{\sin }^{2}}(a+y)}\Rightarrow \frac{dy}{dx}=\frac{{{\sin }^{2}}(a+y)}{\sin a}\]
You need to login to perform this action.
You will be redirected in
3 sec
