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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2000

  • question_answer
    If g is the inverse function of \[f\] and \[f'(x)=\frac{1}{1+{{x}^{n}}},\] then the value of\[g'(x)=\]

    A)  \[{{(g(x))}^{n}}\]                            

    B)  \[1+{{(g(x))}^{n}}\]

    C)  \[1-{{(g(x))}^{n}}\]                        

    D)  zero

    Correct Answer: B

    Solution :

    Given \[g(x)\]is the inverse of \[f(x)\]and \[f'(x)=\frac{1}{1+{{x}^{n}}}g'(x)=1+{{(g(x))}^{n}}\]


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