CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    A bus is moving with a velocity of 5 m/s towards a huge well. The driver sounds a horn of frequency 165 Hz. If the speed of sound in air is 355 m/s, the number of beats heard per second by a passenger on the bus will be:

    A)  6                                            

    B)  5

    C)  3                            

    D)  4

    Correct Answer: B

    Solution :

    From the formula \[n'=\frac{\upsilon +{{\upsilon }_{0}}}{\upsilon -\upsilon }.\,n\] \[=\frac{335+5}{335-5}\times 165=170\,Hz\] Hence no. of beats heard per second by the passenger is \[=170-165=5\,\text{beats/sec}\]


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