A) \[38.85\text{ }cm\]of Hg
B) \[21.85\text{ }cm\]of Hg
C) \[10.85\text{ }cm\] of Hg
D) \[~14.85\text{ }cm\] of Hg
Correct Answer: C
Solution :
Volume of first cylinde \[{{V}_{1}}=5\]litres Volume of second cylinder\[{{V}_{2}}=30\]litre Hence, total volume \[{{V}_{2}}={{V}_{1}}+{{V}_{2}}=5+30=35\,\text{litre}\] The initial pressure pi at NTP \[{{P}_{1}}=76\,cm\]of \[Hg\] Now from the Boyle's law, \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] Hence \[{{P}_{2}}=\left( \frac{{{V}_{1}}}{{{V}_{2}}} \right){{P}_{1}}\] \[=\frac{5}{35}\times 76=10.85\,cm\]of Hg
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