A) \[0.4%\]
B) \[0.2%\]
C) \[0.1%\]
D) \[0.8%\]
Correct Answer: A
Solution :
Initial temperature \[{{T}_{1}}=250\,K\] Final temperature \[{{T}_{2}}=250+1=251\,K\] From the Charle's law, \[\frac{{{P}_{1}}}{{{P}_{2}}}=\frac{{{T}_{1}}}{{{T}_{2}}}\] \[{{P}_{2}}=\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right){{P}_{1}}\] \[=\frac{251\times 1}{250}=1.004\] Hence, change in pressure, \[=1.004-1=0.004=0.4%\]
You need to login to perform this action.
You will be redirected in
3 sec
