A) 2
B) 4
C) zero
D) 1
Correct Answer: C
Solution :
\[\left| \begin{matrix} 41 & 42 & 43 \\ 44 & 45 & 46 \\ 47 & 48 & 49 \\ \end{matrix} \right|\begin{matrix} \text{Applying} \\ {{C}_{2}}-{{C}_{1}} \\ {{C}_{3}}-{{C}_{2}} \\ \end{matrix}\]\[=\left| \begin{matrix} 41 & 1 & 1 \\ 44 & 1 & 1 \\ 47 & 1 & 1 \\ \end{matrix} \right|=0\] Since two columns are identical.
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