2. Solved Papers
  3. CET Karnataka Engineering

CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2001

  • question_answer
    If sixth term of a H.P is\[\frac{1}{61}\] and its tenth term is\[\frac{1}{105},\] then first term of that H.P. is:

    A)  1/38                                     

    B)  1/39

    C)  1/6                                       

    D)  1/17

    Correct Answer: C

    Solution :

    \[{{T}_{6}}=\frac{1}{61},{{T}_{10}}=\frac{1}{105}\]sixth term are in A.P. \[a+5d=61...(i)\]tenth term are in A.P. \[a+9d=105...(ii)\] Solving (i) and (ii)\[a=6,\]the H.P the first term 1/6


You need to login to perform this action.
You will be redirected in 3 sec spinner