CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2002

  • question_answer
    A ray of light travels from an optically denser to a rarer medium. The critical angle for the two media is C. The maximum possible deviation of the ray will be :

    A) \[2C\]                                   

    B) \[\frac{\pi }{2}-C\]

    C)  \[\pi -C\]                            

    D)  \[\pi -2C\] 

    Correct Answer: B

    Solution :

    \[OA\text{ }=\]incident ray \[\Delta S=\]interface which separates the two medium. \[OB=\]actual path of the incident ray. \[\angle C=\]critical angle. \[\angle QOB\]is also \[=\angle C\] After incidence ray refract towards OS. \[\therefore \]Deviation \[(\delta )=\angle BOS\] \[=\frac{\pi }{2}-C\]


You need to login to perform this action.
You will be redirected in 3 sec spinner