A) elimination
B) poly merisation
C) dimerisation
D) substitution
Correct Answer: A
Solution :
Haloalkanes on boiling with alcoholic KOH undergoes elimination or dehydrohalogenation \[\underset{\text{Propyl}\,\text{bromide}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}Br}}\,+alc.KOH\xrightarrow{{}}\]\[\underset{\text{Propylene}}{\mathop{C{{H}_{3}}CH}}\,=C{{H}_{2}}+KBr+{{H}_{2}}O\]
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