A) \[{{K}_{2}}=0.25\,{{K}_{1}}\]
B) \[{{K}_{2}}\approx 0.5\,{{K}_{1}}\]
C) \[{{K}_{2}}\approx 4{{K}_{1}}\]
D) \[{{K}_{2}}\approx 2{{K}_{1}}\]
Correct Answer: A
Solution :
By the increase in temperature the activation energy decreases. So the rate of reaction increases. Here temperature difference is 20 K. At 10 K the rate constant is doubled. Therefore, here it is four times. Hence \[{{K}_{2}}=0.25\,K.\]
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