CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2002

  • question_answer
    The differential of \[{{e}^{{{x}^{3}}}}\]with respect to \[\log x\] is:

    A)  \[{{e}^{{{x}^{3}}}}\]                                      

    B)  \[3{{x}^{2}}{{e}^{{{x}^{3}}}}+3{{x}^{2}}\]

    C)  \[3{{x}^{3}}{{e}^{{{x}^{3}}}}\]                  

    D)  \[3{{x}^{3}}{{e}^{{{x}^{3}}}}\]

    Correct Answer: D

    Solution :

    \[4={{e}^{{{x}^{3}}}},\,\,\upsilon =\log x\] \[\frac{du}{dx}=3{{x}^{2}}{{e}^{{{x}^{3}}}},\frac{d\upsilon }{dx}=1/x\] \[\frac{du}{d\upsilon }=3{{x}^{3}}{{e}^{{{x}^{3}}}}\]


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