A) \[450\text{ }c{{m}^{3}}\]
B) \[100\text{ }c{{m}^{3}}\]
C) \[45\text{ }c{{m}^{3}}\]
D) \[400\text{ }c{{m}^{3}}\]
Correct Answer: D
Solution :
Let, \[x\,\,ml\] of \[HCl\] are taken, then \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[\frac{1}{2}\times x=\frac{1}{10}\times 500\] \[\frac{1}{2}\times x=\frac{1}{10}\times 500\] \[x=100\,\,mL\] Hence, water needed to add = 500 - 100 = 400 mL
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