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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    Solubility product of a salt AB is \[1\times {{10}^{-8}}\] in a solution in which concentration of A is \[{{10}^{-3}}M\]. The salt will precipitate when the concentration of B becomes more than :

    A)  \[{{10}^{-4}}M\]                             

    B)  \[{{10}^{-7}}M\]

    C)  \[{{10}^{-6}}M\]                             

    D)  \[{{10}^{-5}}M\]

    Correct Answer: D

    Solution :

    For binary salt AB,                                 \[{{K}_{sp}}={{s}^{2}}=[A][B]\]                 \[\therefore \]  \[{{10}^{-8}}={{10}^{-3}}\times [B]\]                 \[\therefore \]  \[[B]={{10}^{-5}}M\] Hence, when [B] will be more than \[{{10}^{-5}}\] M, the salt will be precipitated.


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