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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2003

  • question_answer
    The number of a and P particles emitted during the transformation of \[_{90}T{{h}^{232}}\] to \[_{82}P{{b}^{208}}\] are respectively :

    A)  4, 2                                       

    B)  2, 2

    C)  8, 6                                       

    D)  6, 4

    Correct Answer: D

    Solution :

    No. of \[\alpha \]-particles \[=\frac{1}{4}\times \] (Difference in mass number)                 \[=\frac{1}{4}\times (232-208)=\frac{1}{4}\times 24=6\] No. of \[\beta \]-particles \[=2\times \]\[\alpha \]-particles (Difference in atomic number)                 \[=2\times 6-(90-82)=12-8=14\]


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