A) 4000 years
B) 5700 years
C) 8100 years
D) 6000 years
Correct Answer: C
Solution :
We know that, \[\frac{dN}{d\,t}=\lambda .N\] \[\therefore \] \[1.18\times {{10}^{13}}=\frac{1}{T}\times \frac{1}{12}\times 6.023\times {{10}^{23}}\] or \[T=\frac{6.023\times {{10}^{23}}}{1.18\times {{10}^{13}}\times 12}\] minutes \[T=\frac{6.23\times {{10}^{23}}}{1.18\times {{10}^{13}}\times 12\times 60\times 24\times 365}\] years = 8100 years
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