CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2004

  • question_answer
    A bullet moving with a speed of \[100\text{ }m{{s}^{-1}}\] can just penetrate two planks of equal thickness. Then, the number of such planks penetrated by the same bullet when the speed is doubled will be:

    A)                  6                                            

    B)                  10

    C)  4                                            

    D)  8

    Correct Answer: D

    Solution :

    Let the thickness of each plank is d. From. equation of motion                 \[{{\upsilon }^{2}}={{u}^{2}}+2\,as\]                                       ... (i) Ist case; \[s=2\,d,\,u=100\,\,m{{s}^{-1}},\upsilon =0\] \[\therefore \]  \[0={{(100)}^{2}}+2a\times 2d\] \[\Rightarrow \]               \[4ad=-100\times 100\] \[\Rightarrow \]               \[a=-\frac{100\times 100}{4d}\] \[\therefore \]  \[a=-\frac{2500}{d}\]                                      ... (2) (- ve sign stands for retardation) IInd case; Let the bullet with double the previous speed will penetrate n planks of equal thickness d. Now, \[\upsilon =0,\,u=200\,m{{s}^{-1}},a=-\frac{2500}{d},\,s=nd\] Using equation (1) again, we have                 \[0={{(200)}^{2}}-2\times \frac{2500}{d}\times nd\] \[\Rightarrow \]               \[n=\frac{200\times 200}{2\times 2500}=8\]


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