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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2004

  • question_answer
    4g of copper was dissolved in concentrated nitric acid. The copper nitrate solution on strong heating gave 5 g of its oxide. The equivalent weight of copper is:

    A)  23                                         

    B)  32

    C)  12                                         

    D)  20

    Correct Answer: B

    Solution :

    Weight of copper oxide = 5 g Weight of copper taken = 4 g \[\therefore \] Weight of oxygen in copper oxide                 = 5 - 4 = 1g \[\because \]  Weight of copper, reacted with 1g.                 \[{{O}_{2}}=4\,g\] \[\therefore \] Weight of copper, which would react with \[8\,g\,{{O}_{2}}=\frac{4\times 8}{1}=32\,g\]. Hence, equivalent weight of copper = 32


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