A) 7
B) 9
C) 1
D) 3
Correct Answer: C
Solution :
Given that \[{{7}^{300}}\] \[\therefore \] \[{{7}^{1}}=7,\,{{7}^{2}}=7\times 7=49\], \[{{7}^{3}}=7\times \,7\times 7=243\] \[{{7}^{4}}=7\times \,7\times 7\times 7=2401\] \[{{7}^{5}}=7\times \,7\times 7\times 7\times \,7=16807\] and \[{{7}^{300}}={{7}^{4\times 75}}\] \[\Rightarrow \] Last digit of \[{{7}^{300}}\] will be 1
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