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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    15 moles of \[{{H}_{2}}\] and 5.2 moles of \[{{I}_{2}}\] are mixed and allowed to attain equilibrium at   \[{{500}^{o}}C\]. At equilibrium, the concentration of HI is found to be 10 moles. The equilibrium constant for the formation of HI is :

    A)  50                                         

    B)  15

    C)  100                                       

    D)  25

    Correct Answer: A

    Solution :

    \[\underset{\begin{smallmatrix}  15 \\  (15-5) \end{smallmatrix}}{\mathop{{{H}_{2}}}}\,\,\,+\,\underset{\begin{smallmatrix}  5.2 \\  (5.2-5) \end{smallmatrix}}{\mathop{{{I}_{2}}}}\,\,\,\underset{\begin{smallmatrix}  0 \\  10 \end{smallmatrix}}{\mathop{2HI}}\,\] Equilibrium constant \[({{K}_{c}})=\frac{{{(HI)}^{2}}}{[{{H}_{2}}]\,\,[{{I}_{2}}]}=\frac{10\times 10}{10\times 0.2}=50\]


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