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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    A mixture of two moles of carbon monoxide and one mole of oxygen, in a closed vessel is ignited to convert the carbon monoxide to carbon dioxide. If \[\Delta H\] is the enthalpy change and \[\Delta E\] is the change in internal energy, then:

    A)  \[\Delta H>\Delta E\]

    B)  \[\Delta H<\Delta E\]

    C)  \[\Delta H=\Delta E\]

    D)  the relationship depends on the capacity of the vessel

    Correct Answer: B

    Solution :

    \[2CO+{{O}_{2}}\xrightarrow{{}}2C{{O}_{2}}\]                 \[\Delta H=\Delta E+\Delta nRT\] \[\Delta n=\]No. of moles of gaseous product - No. of moles of gaseous reactant                 \[\Delta n=2-3=-1\]                 \[\Delta H=\Delta E-RT\] \[\therefore \]  \[\Delta H<\Delta E\]


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