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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    The hydrogen electrode is dipped in a solution of pH 3 at \[{{25}^{o}}C\]. The potential would be (the value of 2.303 RT/F is 0.059 V) :

    A)  0.177 V                               

    B)  0.087 V

    C)  0.059V                                

    D)  -0.177V

    Correct Answer: D

    Solution :

    \[pH=3,\,\,[{{H}^{+}}]={{10}^{-3}}\] \[E={{E}^{o}}_{red}+0.059\,\log \,\,(ion)\] \[E=0+0.059\,\,\log \,({{10}^{-3}})\] \[E=+0.059\,(-3)=-0.177\,\,V\]


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