A) (3, 3)
B) (2,-1)
C) (-2,1)
D) (-1,2)
Correct Answer: B
Solution :
Given parametric equations are \[x=2+3\cos \theta ,\,y=3\,\sin \theta -1\] or \[\cos \theta =\frac{x-2}{3},\,\sin \theta =\frac{y+1}{3}\] since, \[{{\sin }^{2}}\theta +{{\cos }^{2}}\theta =1\] \[\Rightarrow \] \[{{\left( \frac{x-2}{3} \right)}^{2}}+{{\left( \frac{y+1}{3} \right)}^{2}}=1\] \[\Rightarrow \] \[{{(x-2)}^{2}}+{{(y+1)}^{2}}={{3}^{2}}\] \[\therefore \] Centre of circle is (2, -1).
You need to login to perform this action.
You will be redirected in
3 sec
