CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2005

  • question_answer
    The circus-radius of the triangle whose sides are 13, 12 and 5, is :

    A)  15                                         

    B)  13/2

    C)  15/2                                    

    D)  6

    Correct Answer: B

    Solution :

    Let sides are \[a=13,b=12,\,c=5\]. Now,     \[{{a}^{2}}={{b}^{2}}+{{c}^{2}}\] \[\Rightarrow \]               \[{{(13)}^{2}}+{{(12)}^{2}}+{{5}^{2}}\] \[\Rightarrow \]               \[169=169\] \[\Rightarrow \]               \[\angle A={{90}^{o}}\] We know, \[R=\frac{a}{2\sin A}\]                 \[R=\frac{13}{2\,\,.\,\,\sin {{90}^{o}}}=\frac{13}{2}\]


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