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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2006

  • question_answer
    A gang capacitor is formed by interlocking a number of plates as, shown in figure. The distance between the consecutive plates is 0.885 cm and the overlapping area of the plates is \[5\text{ }c{{m}^{2}}\]. The capacity of the unit is:

    A)                  1.06 pF                                

    B)  4 pF

    C)  6.36 pF                                

    D)  12.72 pF

    Correct Answer: B

    Solution :

    The given arrangement of nine plates is equivalent to the parallel combination of 8 capacitors. The capacity of each capacitor,                 \[C=\frac{{{\varepsilon }_{0}}\,A}{d}\]                 \[=\frac{8.854\times {{10}^{-12}}\times 5\times {{10}^{-4}}}{0.885\times {{10}^{-2}}}=0.5\,pF\] Hence, the capacity of 8 capacitors                 \[=8C=8\times 0.5=4pF\]


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