CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2006

  • question_answer
    A monoatomic gas is suddenly compressed to \[{{(1/8)}^{th}}\] of its initial volume adiabatically The ratio of its final pressure to the initial pressure is: (Given the ratio of the specific heats of the given gas to be 5/3)

    A)  32                                         

    B)  40/3

    C)  24/5                                     

    D)  8

    Correct Answer: A

    Solution :

    In an adiabatic process,                 \[P{{V}^{\gamma }}=\] constant \[\Rightarrow \]               \[\frac{{{P}_{1}}}{{{P}_{2}}}={{\left( \frac{{{V}_{2}}}{{{V}_{1}}} \right)}^{\gamma }}\] \[\Rightarrow \]               \[\frac{{{P}_{1}}}{{{P}_{2}}}={{\left( \frac{1}{8} \right)}^{5/3}}\] \[\Rightarrow \]               \[\frac{{{P}_{1}}}{{{P}_{2}}}={{\left( \frac{1}{{{2}^{3}}} \right)}^{5/3}}\]                 \[=\frac{1}{32}\] \[\therefore \]  \[\frac{{{P}_{2}}}{{{P}_{1}}}=32\]


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