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CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2006

  • question_answer
    The gcd of 1080 and 675 is :

    A)  145                                       

    B)  135

    C)  225                                       

    D)  125

    Correct Answer: B

    Solution :

    Now,  \[1080\div 675\] \[\begin{align}   & 675)1080(1 \\  & \underset{\_\_\_\_\_}{\mathop{675}}\, \\  & 405)675(1 \\  & \underset{\_\_\_\_\_}{\mathop{405}}\, \\  & 270)405(1 \\  & \underset{\_\_\_\_\_}{\mathop{270}}\, \\  & 135)270(2 \\  & 270 \\  & \underset{\_\_\_\_}{\mathop{\underset{0}{\mathop{\_\_\_\_}}\,}}\, \\ \end{align}\] \[\therefore \]The gcd of \[1080\] and \[675\] is\[135\].


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