A) \[\{(a,c),(a,d)\}\]
B) \[\{(a,\text{ }6),(c,\text{ }d)\}\]
C) \[\{(c,\text{ }a),(d,\text{ }a)\}\]
D) \[\{(a,\text{ }c),(a,\text{ }d),(b,\text{ }d)\text{ }\!\!\}\!\!\text{ }\]
Correct Answer: A
Solution :
Given that \[A=\{a,b,c\},B=\{b,c,d\}\] and \[C=\{a,d,c\}\] Now, \[A-B=\{a,b,c\}-\{b,c,d\}\] \[\{a\}\] and \[B\cap C=\{b,c,d\}\cap \{a,d,c\}\] \[\{c,d\}\] \[\therefore \] \[(A-B)\times (B\cap C)=\{a\}\times \{c,d\}\] \[=\{(a,c),(a,d)\}\]
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