A) 160 J
B) zero
C) 5 J
D) 1.25 J
Correct Answer: D
Solution :
Loss of energy \[=\frac{1}{2}\frac{{{C}_{1}}{{C}_{2}}}{({{C}_{1}}+{{C}_{2}})}\,{{({{V}_{1}}-{{V}_{2}})}^{2}}\] \[=\frac{1}{2}\frac{5\times {{10}^{-6}}\times 5\times {{10}^{-6}}{{(2000-1000)}^{2}}}{(5+5)\times {{10}^{-6}}}\] \[=\frac{5\times 5}{2\times 10}=1.25\,J\]
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