A) \[1\times {{10}^{2}}m{{s}^{-1}}\]
B) \[1.56\times {{10}^{-2}}m{{s}^{-1}}\]
C) \[1.56\times {{10}^{-3}}m{{s}^{-1}}\]
D) \[1\times {{10}^{-2}}m{{s}^{-1}}\]
Correct Answer: B
Solution :
Drift velocity, \[{{v}_{d}}=\frac{I}{neA}\] \[\Rightarrow \] \[{{v}_{d}}=\frac{5}{(5\times {{10}^{26}})\times (1.6\times {{10}^{-19}})\times (4\times {{10}^{-6}})}\] \[=\frac{1}{64}=1.56\times {{10}^{-2}}m{{s}^{-1}}\]
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