CET Karnataka Engineering CET - Karnataka Engineering Solved Paper-2007

  • question_answer
    In Young's double slit experiment with sodium vapour lamp of wavelength 589 nm and the slits 0.589 mm apart, the half angular width of the central maximum is

    A)  \[{{\sin }^{-1}}\left( 0.01 \right)\]                           

    B)  \[{{\sin }^{-1}}\left( 0.0001 \right)\]

    C)  \[{{\sin }^{-1}}\left( 0.001 \right)\]         

    D)  \[{{\sin }^{-1}}\left( 0.1 \right)\]

    Correct Answer: C

    Solution :

    In Young's double slit experiment half angular width is given by                 \[\sin \theta =\frac{\lambda }{d}\]                 \[=\frac{589\times {{10}^{-9}}}{0.589\times {{10}^{-3}}}={{10}^{-3}}\] \[\Rightarrow \]               \[\theta ={{\sin }^{-1}}(0.001)\]


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